Question

the amount of work done in forming a soap film of size 5cm *15 cm if surface tension is 10^-2 N/m is

Answer 1

Work done will be $75\times 10^{-6}J$

Explanation:

We have given tension $T=10^{-2}N/m$

Change in area is given as $\Delta A=5cm\times 15cm=75cm^2=75\times 10^{-4}m^2$

We have t find the work done

We know that when change in area is very small then work done is given by

Work done = tension × change in area

So work done $W=10^{-2}\times 75\times 10^{-4}=75\times 10^{-6}J$

Learn more

Work done in increasing the area of soap bubble

https://brainly.in/question/13105858