Chemistry, asked by abhaSingh, 1 year ago

the amount of zinc necessary to produce 224 ml of H2 by the reaction with an acid will be

Sidhant2812: First work out how many moles of H2 are produced. I assume the 224mL is measured at STP. One mole of ideal gas occupies 22.4L at STP, so 224mL of H2 gas contains 224mL/22.4L = 10 mmol of H2 molecules.

Next write an equation for the reaction :
Zn + 2H(+) ---> Zn(2+) + H2.
From this we see that 1 mol of Zn produces 1 mol of H2, so we require 10 mmol of Zn for the reaction.

1 mol of Zn has a mass of 65.4g, so 10 mmol of Zn has a mass of 654 mg = 0.654 g.

Answer : 0.654 g.

Sidhant2812: question from my pearson book

Aakashsuryawanshi: 8==D

Answers

Answered by vanah1

ok i will prove ok i will send to u dont worry

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