Question

The amount of zinc required to produce 224ml of H2 at ntp on treatment with H2SO4 will be in gram

Answer 1

Answer:

0.65g

Explanation:

zn + h2so4 ---> znso4 + h2

65g. 22.4l

65 g of zn is equivalent to 22.4l of h2

so, 224 ml is equivalent to (65 × 224)/22400

= 0.65g

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