Question

The amount on Rs.10, 000 for 2 years at 5% p.a compounded annually

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Answer 1

$\bf \: \underline{Given} :$ ↴

$\sf \: Principal : Rs.\: 10,000$

$\sf \: Time : 2 \: Years$

$\sf \: Rate \: of \: Interest : 5 \: \%$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: the \: Amount.$

$\sf \: As \: we \: know \: that,$

$\boxed{ \pink{\sf \: Amount = P\bigg\lgroup1+ \dfrac{R}{100}\bigg \rgroup^{n}}}$

$\sf \: Where,$

$\sf \bull \longrightarrow \: \: P = Principal$

$\sf \:\bull \longrightarrow \: R = Rate \: of \: Interest$

$\sf \: \bull \longrightarrow \: n = Time$

$\sf \: \underline{ Putting \: the \: values}$

$\sf \: \longmapsto 10000 \bigg\lgroup 1+ \dfrac{5}{100} \bigg \rgroup^{2}$

$\sf \: \longmapsto 10000 \bigg\lgroup 1+ \dfrac{1}{20} \bigg \rgroup^{2}$

$\sf \: \longmapsto 10000 \bigg\lgroup \dfrac{20 + 1}{20} \bigg \rgroup^{2}$

$\sf \: \longmapsto \: 10000 \bigg\lgroup \dfrac{21}{20} \bigg \rgroup^{2}$

$\sf \: \longmapsto \: 10000 \bigg\lgroup \dfrac{21}{20} \times \dfrac{21}{20}\bigg \rgroup$

$\sf \: \longmapsto \: 10000 \bigg\lgroup \dfrac{441}{400} \bigg \rgroup$

$\sf \: \longmapsto \: 10000 \times \dfrac{441}{400}$

$\sf \: \longmapsto \: 25 \times \dfrac{441}{1}$

$\sf \: \longmapsto \: 25 \times 441$

$\sf \: \longmapsto \: 11025$

$\underline{ \green{ \boxed{ \pink{ \sf \: Thus, \: Amount = Rs. \: 11025}}}}$