The amplitude and time period in a s.h.m is 0.5cm and 0.4sec respectively
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Explanation:
Given The amplitude and time period in a s.h.m is 0.5 cm and 0.4sec respectively. If the initial phase is π/2 radian, then the equation of S. h.M will be
- We know that x = a sin (ωt + φ) so φ is the phase difference.
- At t=0, it will be π/2
- So x = 0.5 sin (2π/0.4 x t + φ)
- Now x = 0.5 sin (5π x t + π/2)
- Sin (π/2 + θ) will be positive
- Now x = 0.5 sin (5πt + π/2)
So x = 0.5 cos 5 π t
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