The amplitude and time period of a particle executing SHM are A and T respectively. The speed of the particle x=A/2 will be
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the displacement of a point x subject to SHM is X = a sin T
the speed v of that point is v = a cos T
when v =(a cos T )/2 then arc cos (0.5)=60°
at this speed the displacement X = a sin 60°=0.866a
the displacement of a point x subject to SHM is X = a sin T
the speed v of that point is v = a cos T
when v =(a cos T )/2 then arc cos (0.5)=60°
at this speed the displacement X = a sin 60°=0.866a
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