Question

the angel of a quadrilateral are (2x+4)°,(2x-1),°(2x+5),°2(3x+2),° respectively.find the value of x.​

Answer 1

●■▪$\huge\pink{Ram\:Ram}$▪■●

We know that sum of Angles of quadrilateral is 180°.

According to Question: -

(2x+4)°+(2x-1)°+(2x+5)°+2(3x+2)°=180°

2x+4°+2x-1°+2x+5°+6x+4=180°

12x+12°=180°

12x=180°-12°

12x=168

$x = \frac{168}{12}$

$x = 14$

x=14° is the answer.

Hope it helps uhh❣❣

please mark me as a Brainlist and follow me plz.❣❣