Question

the angel of a quadrilateral are x degree (x–10),(x+30)and (2x), the smallest angle is equal to​

Answer 1

Hi ,

sum of the angles in a quadrilateral = 360

x + ( x - 10 ) + ( x + 30 ) + 2x = 360

x + x + x + 2x -10 +30 = 360

5x + 20 = 360

5x = 360 - 20

5x = 340

x = 340 / 5

x = 68

first angle = x = 68°

second angle = x - 10 = 68 - 10 = 58°

third angle = x + 30 = 68 + 30 = 98°

fourth angle = 2x = 2 × 68 = 136°

i hope this useful to you .

: )

Answer 2

sum of angles of quadrilateral is 360

x+(x-10)+(x+30)+(2x) =360

5x+20=360

5x=340

x=340/5

=68

smallest angle is (x-10)=58