the angle A of a triangle ABC is equal to the sum of other two angles.Also ,the ratio of the angle B to the angle C is 4:5. find the measure of each angle
Answers
Answered by
72
By angle sum property of triangle,
A+B+C=180
(4x+5x)+4x+5x=180
9x+9x=180
18x=180
x=10
A=9x=90
B=4x=40
C=5x=50
A+B+C=180
(4x+5x)+4x+5x=180
9x+9x=180
18x=180
x=10
A=9x=90
B=4x=40
C=5x=50
Answered by
60
Hi ,
According to the problem given,
We know that,
Sum of the three angles in a triangle
Is equals to 180°
A + B + C = 180----( 3 )
A + A = 180 [ from ( 1 ) ]
2A = 180
A = 180 / 2
A = 90 ---- ( 4 )
Put A = 90 in ( 3 ).,
90 + B + C = 180
B+ C = 90
4C/5 + C = 90 [ from ( 2 ) ]
( 4C + 5C ) / 5 = 90
9C = 450
C = 450 / 9
C = 50
Put C = 50 in ( 2 )
B = ( 4 × 50 ) / 5
B = 4 × 10
B = 40
Therefore ,
A = 90 , B = 40° , C = 50°
I hope this helps you.
:)
According to the problem given,
We know that,
Sum of the three angles in a triangle
Is equals to 180°
A + B + C = 180----( 3 )
A + A = 180 [ from ( 1 ) ]
2A = 180
A = 180 / 2
A = 90 ---- ( 4 )
Put A = 90 in ( 3 ).,
90 + B + C = 180
B+ C = 90
4C/5 + C = 90 [ from ( 2 ) ]
( 4C + 5C ) / 5 = 90
9C = 450
C = 450 / 9
C = 50
Put C = 50 in ( 2 )
B = ( 4 × 50 ) / 5
B = 4 × 10
B = 40
Therefore ,
A = 90 , B = 40° , C = 50°
I hope this helps you.
:)
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