the angle between the 2 vectors Abar is equal to 5ikab +5jkab and Bbar is equal to 5ikab -5jkab will be
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Magnitude of vector 1 is 5 root 2 and 2nd vector is also 5 root 2 so a.b = ab cos theta so a.b=0 and ab cos theta = 50 cos thetha so cos thetha =0 so thetha = 90degree
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