Question

The angle between the vectors : a=3î-4j and b=-2î+3k

Answer 1

|A| = √3² + 4²

|A| = √9+16

|A| = 5

|B| = √2²+3²

|B| = √4+9

|B| = √13

A•B = ( 3i – 4j + 0k ) ( – 2i + 0j + 3k )

A•B = –6 + 0 + 0

A•B = – 6

CosΦ = |A| |B| / ( A•B )

CosΦ = 5√13 / –6

Φ = cos-¹ ( 5√13 / – 6 )

Should be the answer. Please check once