Question

the angle between the vectors a vector is equal to two ICAP + 2 J cap - 2 k cap and b vector is equal to 3 ICAP - 4 j cap is​

Answer 1

Answer:the answer is given below plz check it out

Explanation:

Answer 2

The angle between vectors A and B is 96.63 degrees.

Explanation:

It is given that,

Vector, $A=2i+2j-2k$

Vector, $B=3i-4j$

We need to find the angle between A and B. It an be calculated using dot product formula such that,

$A.B=|A||B|\ cos\theta$

Magnitude of A, $|A|=\sqrt{2^2+2^2+2^2} =3.464$

Magnitude of B, $|B|=\sqrt{3^2+(-4)^2} =5$

Dot product of A and B, $A.B=6-8+0=-2$

$cos\theta=\dfrac{A.B}{|A||B|}$

$cos\theta=\dfrac{-2}{3.464\times 5}$

$\theta=96.63^{\circ}$

So, the angle between vectors A and B is 96.63 degrees. Hence, this is the required solution.

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Dot product

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