Question

The angle between two Pull forces of magnitude 10N and 20N is 60, 20N force being horizontal.
Determine the resultant in magnitude and direction.

Answer 1

Answer:

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Explanation:

The x components of the forces are  103√2N  and  10N . The y components are  ±5  and  ±203√2N .

So the x component of the resultant is  (53–√+10)N , and the y component is  (±5+±103–√)N . Decide on the signs and you will have an answer.

or

Two forces of magnitude F1= 10N and F2 =20N act on a body in a direction making angle a = 30 and b = 60 degrees respectively with the x-axis. Thus the resultant force Fr acting on the body is given by,

Fr = i (F1 cos a + F2 cos b) + j ( F1 sin a + F2 sin b)

= i ( 10 cos 30 + 20 cos 60) + j ( 10 sin 30 + 20 sin 60).

= i { 10 x (√3/2) + (20 /2)} + j { (10/2)+ 20 x(√3/2)}

= i (5 √3 + 10) + j (5 + 10√3) N