Question

The angle between two vectors -2i+3j+k and i+2j-4i

Answer 1

Answer:

Angle is given as cosθ=

∣A∣∣B∣

A

.

B

Thus, cosθ=

9+16+25

(3

i

^

+4

j

^

+5

k

^

).(3

i

^

+4

j

^

−5

k

^

)

=0

cosθ=0

Thus θ=90

0