The angle between two vectors -2i+3j+k and i+2j-4k is A. 0 degree B. 90 degree C. 180 degree
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Let, a = 2i-3j+k and b = i+2j+4k
We know that, a.b=ab cos∅
So, cos∅= a.b/ab
a.b= 2–6+4= 0
So, cos∅= 0/ab
cos∅= 0
cos∅=cos90°
Hence, angle between the vectors a & b is 90° or π/2 radians
Hope it helps!!
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