Question

The angle of a cyclic quadrilateral abcd are angle a = (2x+4)

Answer 1

plz write your question completely and properly

Answer 2

Answer:

Step-by-step explanation:

A + C = ( 2x - 1) + ( 2y + 15 ) = 180° ==> x + y = 83°

B + D = (y +5 ) + ( 4x - 7 ) = 180° ==> 4x + y =182°.

Solving these two equation together we get ;

x = 33° & y = 50°. Hence angles of the cyclic quadrilateral are ;

A = 65° , B = 55° , C = 115° & D = 125° .