Math, asked by vinayakmerta7890, 10 months ago

The angle of a elevation to the top of a tower from a point 30m away from the foot of tower on the ground is 30.find the height of tower.





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Answers

Answered by Anonymous
5

Answer:

17.320 m

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

Tan \theta=\frac{Perpendicular}{Base}

Tan30^{\circ}=\frac{AB}{BC}

30 \times \frac{1}{\sqrt{3}}=AB

17.320=AB

Hence The height of tower is 17.320 m

Answered by samriddhsaxena
2

Step-by-step explanation:

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