Question

The angle of a elevation to the top of a tower from a point 30m away from the foot of tower on the ground is 30.find the height of tower.





plzzz answer fast☺​

Answer 1

Answer:

17.320 m

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

Tan \theta=\frac{Perpendicular}{Base}

Tan30^{\circ}=\frac{AB}{BC}

30 \times \frac{1}{\sqrt{3}}=AB

17.320=AB

Hence The height of tower is 17.320 m

Answer 2

Step-by-step explanation:

mark as brainliest. ..............