The angle of a pantagon are x , x+20,x+40,x+60,x+80the smallest angle of the pantagon
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Answered by
1
Hi Mate !!
• By angle sum property of Pentagon according to which the sum of the angles of a Pentagon is 540 we can find the angles !!
adding all the angles !!
x + x + 20 + x + 40 + x + 60 + x + 80 = 540
5x + 200 = 540
5x = 540 - 200
5x = 340
x = 340/5
x = 68
So, x = 68 ... [ smallest angle ]
2nd angle :- x + 20 = 88
3rd angle :- x + 40 = 108
4th angle :- x + 60 = 128
5th angle :- x + 80 = 148 !!
So, smallest angle is 68 !!
• By angle sum property of Pentagon according to which the sum of the angles of a Pentagon is 540 we can find the angles !!
adding all the angles !!
x + x + 20 + x + 40 + x + 60 + x + 80 = 540
5x + 200 = 540
5x = 540 - 200
5x = 340
x = 340/5
x = 68
So, x = 68 ... [ smallest angle ]
2nd angle :- x + 20 = 88
3rd angle :- x + 40 = 108
4th angle :- x + 60 = 128
5th angle :- x + 80 = 148 !!
So, smallest angle is 68 !!
Answered by
0
Hey Mate!!
~~~~~~~~~
Here is your answer :
____________________________
Given,
Sides of pentagon = x , x +20 , x + 40 , x + 60 , x + 80
Sum of all angles in pentagon = 540
ATP,
x + x + 20 + x + 40 + x +60 + x + 80 = 540
5x + 200 = 540
5x = 500 - 200
5x = 340
x = 340/5
x = 68
Therefore,
Smallest angle = x = 68
HOPE THIS HELPS U...
~~~~~~~~~
Here is your answer :
____________________________
Given,
Sides of pentagon = x , x +20 , x + 40 , x + 60 , x + 80
Sum of all angles in pentagon = 540
ATP,
x + x + 20 + x + 40 + x +60 + x + 80 = 540
5x + 200 = 540
5x = 500 - 200
5x = 340
x = 340/5
x = 68
Therefore,
Smallest angle = x = 68
HOPE THIS HELPS U...
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