the angle of a sector of a circle is 90 degre. the ratio of the area of the sector and that of the circle is
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1:4 is the answer.Since it is a quadrant
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Let the radius of circle be r
Area of circle = pi r^2
Angle of sector = 90°
Area of sector = pi r^2 × 90 / 360
= pi r^2 / 4
Required ratio = Area of sector : Area of circle
= [(pi r^2) /4] / (pi r^2)
= 1/4
= 1:4
Area of circle = pi r^2
Angle of sector = 90°
Area of sector = pi r^2 × 90 / 360
= pi r^2 / 4
Required ratio = Area of sector : Area of circle
= [(pi r^2) /4] / (pi r^2)
= 1/4
= 1:4
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