Question

The angle of a triangle are
(2x + 10)° , (3x - 20)° and (x + 40)°.
Find the angle​

Answer 1

Given:-

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• The angle of a triangle are (2x + 10)° , (3x - 20)° and (x + 40)°

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To Find:-

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• The Angle

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STEP BY STEP EXPLANATION:-

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The Sum of the angles of a traingle is 180° hence :

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(2x + 10)° + (3x - 20)° + (x + 40)° = 180°

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$\bf \implies6x + {30}^{o} = {180}^{o} \\ \\ \bf \implies6x = {150}^{o} \implies x = {25}^{o}$

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Therefore,

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2x + 10° = 2 × 25° + 10° = 60°

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3x - 20° = 3 × 25° - 25° = 55°

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x = 40° = 25° + 40° = 65°

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Thus, The angles of the triangle are 60° , 55° and 65°

Answer 2

GIVEN :–

• The angle of a triangle are (2x + 10)° , (3x - 20)° and (x + 40)°.

TO FIND :–

• Angle of triangle = ?

SOLUTION :–

• We know that –

⇛ Sum of angles of triangle = 180°

• So that –

⇛ (2x + 10)° + (3x - 20)° + (x + 40)° = 180°

⇛ 2x + 10° + 3x - 20° + x + 40° = 180°

⇛ (2x + 3x + x) + (10° - 20° + 40°) = 180°

⇛ 6x + 30° = 180°

⇛ 6x = 180° - 30°

⇛ 6x = 150°

⇛ x = 150°/6

⇛ x = 25°

▪︎ Hence –

☞ First angle = (2x + 10)° = 2(25°) + 10° = 50° + 10° = 60°

☞ Second angle = (3x - 20)° = 3(25°) - 20° = 75° - 20° = 55°

☞ Third angle = (x + 40)° = 25° + 40° = 65°