The angle of a triangle are x-10,x-20 and 1\2x-10.Find vale of x.
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Question : The angle of a triangle are x-10,x-20 and 2x-10.Find vale of x.
Solution : Value of x is 55°
By Angle sum property, Sum of all angles in a triangle is 180°
( x - 10 ) + ( x - 20 ) + ( 2x - 10 ) = 180
⇒ 2x - 30 + 2x - 10 = 180
⇒ 4x - 40 = 180
⇒4x = 220
⇒x = 220/4
⇒ x = 55 .
Therefore , The value of x is 55°
Solution : Value of x is 55°
By Angle sum property, Sum of all angles in a triangle is 180°
( x - 10 ) + ( x - 20 ) + ( 2x - 10 ) = 180
⇒ 2x - 30 + 2x - 10 = 180
⇒ 4x - 40 = 180
⇒4x = 220
⇒x = 220/4
⇒ x = 55 .
Therefore , The value of x is 55°
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