Question

The angle of depression from the top of a building to the base of a car is 60 . If the building is 708 m tall, how far away is the car?

Answer 1

Refer the attached figure

The angle of depression of a car standing on the ground from the top of a tower is 30 degree i.e. ∠ACB = 30°

Height of the tower = 75 m i.e. AB = 75 m

Now we are supposed to find the distance of the car from the base of the tower i.e. BC

In ΔABC

We will use trigonometric ratio

Hence the distance of the car from the base of the tower is 129.90 m.

Answer 2

Step-by-step explanation:

In right angle triangle ABC the ∠ACB=30

0

(Angle of depression of a car) and the tower is 75 m high

Let the distance of car from ground is x m

Then tan30

0

=

BC

AB

=

x

75

⇒

3

1

=

x

75

⇒x=75

3

m

solution