Question

The angle of depression of a car, parked on

the ground, from the top of a 75 m high tower ,

is 300

.Find the distance of the car from the base

of the tower.​

Answer 1

Answer:

In right angle triangle ABC the ∠ACB=30°

(Angle of depression of a car) and the tower is 75 m high

Let the distance of car from ground is x m

Then tan30°= AB/BC = 75/x

⇒ 1/√3= 75/x

⇒x=75 /√3m

Answer 2

Answer:

There here is your answer.

In right angle traingle ABC the ABC =30°

(Angle of depression of a car and the tower is 75 m high)

Let the distance of car from ground is × m

Then tan30°= AB/BC =75/×

➪ 1/√3 =75/×

➪ ×=75 /√3m