Question

The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. the distance of the car from the tower (in metres) is

Answer 1

I hope this answer helps you

Answer 2

Answer:

259.5m

Step-by-step explanation:

Refer the attached figure.

Height of tower i.e. AB = 150 m.

The angle of depression of a car from the top of the tower i.e. ∠ACB =30°

Distance between the car and the tower is BC

So, to find BC we will use trigonometric ratio.

$tan\theta = \frac{Perpendicular}{base}$

$tan30^{\circ}= \frac{AB}{BC}$

$\frac{1}{\sqrt{3}} = \frac{150}{BC}$

$BC= 150\sqrt{3}$

$BC= 150\times 1.73$

$BC= 259.5 m$

Hence the distance of the car from tower is 259.5 m