Question

the angle of depression of a car standing on the ground from the top of a 75m high tower is 30degree what is the distance of the car from the base of the tower

Answer 1

Answer:

Distance from the car to base of the tower = 129.9 m

Step-by-step explanation:

From the figure,

Height of the tower (AB) = 75m

<ACB = <30°

Distance from the car to base of the tower = CB

$In \:\triangle ABC, \:\angle B = 90°\\</p><p>tan 30\degree = \frac{AB}{BC}$

$\implies \frac{1}{\sqrt{3}}=\frac{75}{BC}$

$\implies BC = 75\times \sqrt{3}\\=75\times 1.732\\=129.9\:m$

Therefore,

Distance from the car to base of the tower = 129.9 m

•••♪

Answer 2

Distance from the car to base of the tower = 129.9 m

From the figure,

Height of the tower$(AB) = 75m$

$< ACB = < 30^\circ$

Distance from the car to base of the tower = CB

In $\triangle ABC$, $\angle B=90^\circ$

$< p > < p > tan30=\frac{AB}{BC}$

$\Rightarrow \frac{1}{\sqrt{3} }=\frac{75}{BC}$

$\RightarrowBC=75\times \sqrt{3}$

$=75\times 1.732$

$=129.9m$

Therefore,

Distance from the car to base of the tower = 129.9 m

#SPJ3