Question

The angle of depression of a car, standing on the ground, from the top of a 75m high tower, is 30° . the distance of the car from the base of the tower (in m.) is:

Answer 1

HEYA!

The answer is in the attachment provided. Please refer to it.

Hope this helps mate!

Answer 2

Answer:

75√3 m

Step-by-step explanation:

Given :

Height of tower i.e. AB = 75 m

The angle of depression of a car, standing on the ground, from the top of tower i.e. ∠ACB is 30°

To Find :The distance of the car from the base of the tower i.e. BC

Solution :

In ΔABC

AB = Height of tower = Perpendicular = 75 m

BC = distance from base of tower to car = Base

∠ACB = 30°

We will use trigonometric ratio to find the length of  base :

$tan\theta = \frac{Perpendicular}{Base}$

$tan30^{\circ} = \frac{AB}{BC}$

$\frac{1}{\sqrt{3}} = \frac{75}{BC}$

$BC= \frac{75}{\frac{1}{\sqrt{3}}}$

$BC= 75\sqrt{3}$

Hence the the distance of the car from the base of the tower is 75√3 m.