Question

the angle of depression of car, standing on the ground, from the top of a75m high tower is ​

Answer 1

Answer:

In right angle triangle ABC the ∠ACB=30°

(Angle of depression of a car) and the tower is 75 m high

Let the distance of car from ground is x m

Then tan30° = AB/BC = 75 /x

⇒ 1/√3= 75/x

⇒x=75√3m

Hope this is helpful for you.