Question

the angle of depression of the top and bottom of a 50m high building from the top of a tower are 45 and 60 degree respectively. find the height of the tower and the horizontal distance between the tower and the building (use $\sqrt{3}$= 1.73)

Answer 1

Answer:

Here CD is the tower and AB is the pole.

In △CDB, CD/BC = tan 60°

=> 50m/BC = √3

=> BC = 50/√3m

AE = BC

AE = 50/√3m

In △ADE, DE/AE = tan 45°

=> DE/50/√3m = 1

=> DE = 50/√3m

so the height of the pole is 50/√3m