the angle of depression of the top and bottom of a building 50 M high as observed from top of a tower are 30 degree and 60 degree respectively find the height of the tower and also the horizontal distance between the building and the tower.
Answers
Answered by
168
this the answer ht of building is 75 and distance between them is 25√3
Attachments:
Answered by
101
Here CD is the tower and AB is the pole.
In △CDB, CD/BC = tan 60°
=> 50m/BC = √3
=> BC = 50/√3m
AE = BC
AE = 50/√3m
In △ADE, DE/AE = tan 45°
=> DE/50/√3m = 1
=> DE = 50/√3m
so the height of the pole is 50/√3m
Similar questions