Question

the angle of elevation and depression of an aeroplane and its image in water are 30 degree and 45 degree from the top of a tree of height 5 m. find hieght at which the aeroplane is fying from its ground​

Answer 1

Answer:

Explanation:

Let space straight A space and space straight B space be space the space positions space of space the space two space aeroplanes

Let space AB space equals space straight x space straight m

Then comma space BC space equals space 3500 space minus space straight x space

as space AC space equals space 3500 space straight m

In space right space increment BCD comma

BC over CD equals tan space 47 degree

CD space equals open parentheses space 3500 space minus space straight x close parentheses cot space 47 degree

CD space equals open parentheses space 3500 space minus space straight x close parentheses cross times 0.9325......... left parenthesis 1 right parenthesis

In space right space increment ACD comma

AC over CD equals tan space 63 degree

3500 over CD equals space tan space 63 degree

CD space equals space 3500 cot space 63 degree

CD space equals space 3500 cross times 0.5095

CD space equals space 1783.25........ left parenthesis 2 right parenthesis

From space left parenthesis 1 right parenthesis space and space left parenthesis 2 right parenthesis comma space we space get

open parentheses 3500 minus straight x close parentheses 0.9325 equals 1783.25

3500 space minus space straight x space equals space 1912.33

straight x space equals space 1587.67 space straight m

Vertical space distance space between space the space two space planes space is space 1587.67 space straight m end style