the angle of elevation from a point 300feet from the base of a pole of height h as the level ground to the top of the pole is 45 the equation can be used to find the height of the pole is
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Step-by-step explanation:
Let AB be the tower and (A, B)
the flag staff, CA=hm
Let D be observation point, such that angle of elevation of top & c bottom, be α & β respectively.
In ΔABD,
tanβ=
BD
AB
BD=ABcotβ …………..(1)
In ΔCBD,
tanα =
BD
CB
BD=CBcotα[∴CB=CA+AB=h+AB]
BD=(h+aB)cotα ………(2)
Equating (1) & (2) equation,
ABcotβ=(h+AB)cotα
ABcotβ=hcotα+ABcotα
AB(cotβ−cotα)=hcotα
AB=
cotβ−cosα
hcotα
AB=
tanβ⋅tanα
tanα−tanβ
tanα
h
AB=h(
tanα−tanβ
tanβ
),
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