Question

The angle of elevation of a cloud from a point 60 metres above a lake is 30° and the angle of depression of its reflection of the cloud in the lake is 60°. Find the height of the cloud.

Answer 1

SOLUTION IS IN THE ATTACHMENT
LINE OF SIGHT: The line of sight is a line drawn from the eye of an observer to the point in the object viewed by the observer.

ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.

ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.

•Angle of elevation and depression are always acute angles.

•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.

HOPE THIS WILL HELP YOU.....

Answer 2

✴hy✴
✳here is your answer ✳

Let AO = H 

CD = OB = 60m

A'B = AB = 60 + H

In  Δ AOD,

⇒ 120 + H = 3H 

⇒ 2 H = 120 

⇒ H = 60 m

Thus, height of the cloud above the lake = AB + A'B = 60 + 60 = 120 m.