.the angle of elevation of a cloud from a point 60m above a lake is 30° and the of depression of the reflection of the cloud in the lake is 60°.find the height of the cloud from the surface of the lake .
Answers
Answered by
2408
Let AO=H
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
CD=OB=60m
A'B=AB=(60+H)m
In triangke AOD,
tan30'=AO/OD=H/OD
H=OD/√3
OD=√3 H
Now, in triangle A'OD,
tan60'=OA'/OD=(OB+BA')/OD
√3=(60+60+H)/√3 H
=(120+H)/√3 H
=>120+H=3H
2H=120
H=60m
Thus, height of the cloud above the lake = AB+A'B
=(60+60)
= 120m
Attachments:
Answered by
424
I hope your helpful answer
by Roshan
Attachments:
Similar questions