the angle of elevation of a cloud from a two point distance 's' and 't' from its feet are complementary. Prove that hight of tower is under root st.
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Solution.
Let, the height of the tower be h. (AB)
AD and AC are the distances from the cloud inclined at a angle (Theta) and (90°-Theta) respectively.
BC=t and BD = s
In the triangleABC,
perendicular=AB=h
and base=BC=t
tan (90°-Theta) = AB/BC
cot theta = h/t.......eq (1)
Now in triangleABD,
perpendicular = AB= h
And base = BD = s
tan theta= AB/BD
= h/s.............eq (2.)
Multiply eq (1.) and eq (2.)
cot Theta × tan Theta = h/t×h/s
1/tan Theta × tan Theta = h^/st
1 = h^/st
st = h^ ( where ^ stands 2.)
h =
Therefore, height of the cloud Underoot st.
Hence, Proved.
Hope this will help you.
Let, the height of the tower be h. (AB)
AD and AC are the distances from the cloud inclined at a angle (Theta) and (90°-Theta) respectively.
BC=t and BD = s
In the triangleABC,
perendicular=AB=h
and base=BC=t
tan (90°-Theta) = AB/BC
cot theta = h/t.......eq (1)
Now in triangleABD,
perpendicular = AB= h
And base = BD = s
tan theta= AB/BD
= h/s.............eq (2.)
Multiply eq (1.) and eq (2.)
cot Theta × tan Theta = h/t×h/s
1/tan Theta × tan Theta = h^/st
1 = h^/st
st = h^ ( where ^ stands 2.)
h =
Therefore, height of the cloud Underoot st.
Hence, Proved.
Hope this will help you.
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MrThakur:
Yeah pic Maine front camera s liya hai.
Answered by
4
Let the height of cloud be x.
Therefore, the height of cloud is
Attachments:
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