The angle of elevation of a jet fighter from a point A on the ground is 60 o . After a flight of 15 seconds, the angle of elevation changes to 30 o. If the jet is flying at a constant height of 1500√3m find (i) The horizontal distance between the two positions of the jet plane .
(ii) The speed of the jet plane in km/h
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ii,
speed = dist / time
DE / 15 sec = speed
1km = 1000m
1hr = 3600 sec
3000m= 3km
15 sec = 15/3600
speed = 3÷ 15/3600
=720 km/hr
speed = dist / time
DE / 15 sec = speed
1km = 1000m
1hr = 3600 sec
3000m= 3km
15 sec = 15/3600
speed = 3÷ 15/3600
=720 km/hr
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alex0071:
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1 . 3000 m
2. 1200 km per hour
2. 1200 km per hour
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