the angle of elevation of a jet plane from a point A on the ground is 60° after 15 sec The angle of elevation changes to 30° if the plane is flying at a constant height of 1500root3 ms find the speed of jet plane
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Let D and E be the initial and final positions of the plane respectively
Consider the triangle ABD
tan60=BDAB√3=1500√3ABAB=1500tan60=BDAB3=15003ABAB=1500
Consider the triangle ACE
tan30=CEAC1√3=1500√3ACAC=4500tan30=CEAC13=15003ACAC=4500
BC = AC - AB = 4500 - 1500 = 3000 m
DE = BC = 3000 m
i.e., the plan travels a distance of 3000 m in 15 seconds.
Therefore, speed of the plane =300015=300015 = 200 m/s
Anonymous:
pehla chaj da answer.
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