Question

The angle of elevation of a stationary cloud from a point 25 m above a lake is 30° and the angle of depression of its reflection in the lake is 60 degree what is the height of the cloud above the lake level

Answer 1

HEY MATE!

ANSWER:

STEP BY STEP EXPLANATION:

Let AE be the height of the tower

BY DATA,

AF=AE

BC=AD=25m

In ∆CDE,

Tan30°=DE/CD

1/√3=AE-AD/CD

1/√3=AE-25/CD

CD=AE√3-25√3 --------1

In ∆ADF,,

Tan 60°=FD/DC

√3=AF+AD/CD

√3=AF+25/AE√3-25√3 (From 1)

√3(AE√3-25√3)=AF+25

3AE-75-25=AF

3AE-100=AF

3AF-AF=100 (AE=AF)

2AF=100

AF=100/2

AF=50m

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AF=AE=50m

THEREFORE,Height of cloud from lake=50m

HOPE IT HELPS!❤

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