Question

the angle of elevation of an aircraft from a point on the horizontal ground is found with 30 degree angle of elevation of aircraft after 24 seconds just moving horizontally to the ground is found be 60 degree if the height of the aircraft from the ground is 3600 root 3 find the velocity aircraft

Answer 1

Refer the attachment for better understanding.

In ΔABC

Tan 30° = AB/BC

     1/√3 = 3600√3 / x+y

    x + y = 3600 × 3

    x + y = 10800 m                      ....................(1)

Also In ΔDEC   DE = AB = Perpendicular distance

Tan 60° = DE/EC

        √3 = 3600√3 / y

          y = 3600 m                        ....................(2)
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From (1) and (2)

x + 3600 = 10800

            x = 10800 - 3600

            x = 7200 m = Distance travelled by aircraft
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Speed = Distance travelled / Time

           = 7200 / 24

           = 300 m/s
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