Question

The angle of elevation of an airplane from a point on the ground is 60". After a flight of 30 seconds.
the angle of elevation becomes 30". If the airplane is flying at a constant height of 3000 V3 m, find the
speed of the airplane
Daily wages of 110 workers, obtained in a survey, are tabulated below:​

Answer 1

Answer:864 km/h

Step-by-step explanation:

In triangle ACE,

CE = 10800 m

AC = BD =

In triangle BED,

CD + DE = CE

CD + 3600 = 10800

CD = 10800 - 3600 = 7200 m

Distance travelled = 7200 m

Time taken = 30 seconds

In 1 second = 240 m

In 3600 seconds (1 hour) = 240 × 3600 = 864000 m = 864 km

In hour = 864 km

Speed = 864 km/h

Answer 2

Answer:

${ \purple{ \tan 60° = \frac{3000 \sqrt{3} }{x} }}$

${ \purple{x= \frac{3000 \sqrt{3} }{ \sqrt{3} } = 3000m}}$

${ \purple{ \tan 30° = \frac{3000 \sqrt{3} }{ \frac{1}{ \sqrt{3} } } = 9000m}}$

Distance covered :

${ \purple{ 9000 - 3000 = 6000m}}$

${ \purple{speed = \frac{6000}{30} }}$

${ \huge{ \boxed{ \purple{speed = 200 m/s}}}}$

Step-by-step explanation:

Hope this helps you ✌️