Question

The angle of elevation of an airplane from a point on the ground is 60°. After a flight of 4
30 seconds, the angle of elevation becomes 30°. If the airplane is flying at a constant
height of 3000v3 m, find the speed of the airplane in m/s​

Answer 1

Answer:

600/43√3

Step-by-step explanation:

distance travelled = 3000/tan30 - 3000/tan60 = 3000*(√3-1/√3) = 6000/√3

speed = 6000/√3/(430) = 600/43√3

Answer 2

Answer:

60/40√3........................