Question

The angle of elevation of the top of a building 150 M high from a point on the ground is 45 degree find the distance of the point from foot of a buildings

Answer 1

let the height of building of 150m is AB
the angle of elevation is 45 from point C
and angle B = 90
now , in right angled triangle ABC
AB/BC = tan45
150/BC = 1. ( tan 45 = 1)
150 = Bc
so distance of building from given point is 150m

Answer 2

Answer is 150m

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