Question

the angle of elevation of the top of a building from a point on the ground which is 9 root 3 metre away from the foot of the building is 60 degree find the height of the building​

Answer 1

Answer: the height of the building would be 27m

Step-by-step explanation:

Answer 2

$In \: \triangle ABC ,$

$Observation \: point \: A .$

$Distance \: from \: foot \: of \:the \: building \\to \: Observation \: point (AB) = 9\sqrt{3} \:m$

$Let \: the \: height \:of \: the \: building (BC)=h \:m$

$tan 60\degree = \frac{BC}{AB}$

$\implies \sqrt{3} = \frac{h}{9\sqrt{3}}$

$\implies \sqrt{3} \times 9\sqrt{3} = h$

$\implies 3 \times 9 = h$

$\implies h = 27 \: m$

Therefore.,

$\red{ Height \: of \:the \: building } \green {= 27 \: m }$

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