The angle of elevation of the top of a building from the foot of the tower is 3
angle of elevation of the top of the tower from the foot of the building is 60°. If the tower
is 30 m high, find the height of the building
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Answer:
ANSWER
Given height of tower CD=50m
Let the height of the building, AB=h
In right angled △BDC,
⇒ tan60
o
=
BD
CD
⇒
3
=
BD
50
⇒ BD=
3
50
m
In right angled △ABD,
⇒ tan30
o
=
BD
AB
⇒
3
1
=
3
50
h
∴
3
1
=
50
3
h
∴ h=
3
50
=16.66m
∴ The height of the building is 16.66m.
Step-by-step explanation:
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