Question

The angle of elevation of the top of a tower 33 m
high from the foot of another tower in the same
plane is 60° and the angle of elevation of the top of
the second tower from the top of the first tower is
30°. Then, the height of the other tower is​

Answer 1

Let the foot distance of one tower be x m and height of another tower be h m

Given height of tower and angle of elevation= 60°

Angle of elevation for second tower = 30 °

tan 60° = √3

33/x=√3

x= 33/√3

x= 11√3

Now for second tower too the foot will be 11√3 as both are in the same plane

Therefore tan 30° = 1/√3

h/11√3= 1/√3

h = 1/√3*11√3

h = 11m

So the height of second tower is 11 m.

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