Question

the angle of elevation of the top of a tower from a point on the ground which is 30 metre away from the foot of the tower is 30 degree find the height of the tower​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

The angle formed by the tower ACB is 30degree

The distance between the BC is 30m.

In triangle ABC,

Tan 30°=AB/BC

Tan 30°=1/√3

So,

1/√3= h/30

Cross multiply both,

√3h=30

H=30/√3

H=30×√3/√3×√3

H=30√3/3

3 and 30 cancels by 3 table and get 10

H=10√3 m