Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower is 30 degree Find the ht. of tower ​

Answer 1

tan 30 = 1/√3

so, 1/√3 = ab/30

⇄ 30 = √3ab

∴ ab = 30/√3

multiplying √3 on numerator and denominator, we get

30√3/3=ab

⇄ 10/√3 = ab

Answer 2

Answer:-

Let us assume that the height of the tower is ‘h’ mtre

In ∆ABC ,

tan30°=AC/BC

1/√3=h/30

30/√3=h

Now to rationalize it we divide numerator and denominator by√3

We get,

10√3= h

Putting √3=1.732

10×1.732=h

17.32=h

Hence the height of the tower is 17.32 cm.

FROM THE FOLLOWING DIAGRAM YOU CAN UNDERSTAND BETTER!!