Question

the angle of elevation of the top of a tower from a point on the ground which is 30 metre away from the foot of the tower is 30 degree find the height of the tower

Answer 1

Answer:

Step-by-step explanation:given,

the angle of elevation= 30 degrees

distance b/w the tower and point=30m

then

tan 30= h/30

1/(3)^0.5 =h/30

h is 17.32 m or 10 *3^0.5

Answer 2

Given :-

• YZ = 30 m

• ∠ XZY = 30°

To find :-

• Height of the tower = ?

Solution :-

Let XY be the height of the tower,

and Z is the point which is 30 m away from the foot of the tower.

Now,

In right ∆ XYZ

$\rm\:tan\:30\degree=\dfrac{p}{b}=\dfrac{XY}{YZ}$

$\rm\longrightarrow\:\dfrac{1}{\sqrt{3}}=\dfrac{XY}{30}$

$\rm\longrightarrow\:XY=\dfrac{30}{\sqrt{3}}$

$\rm\longrightarrow\:XY=10\sqrt{3}\:m$

Hence,the height of the tower (XY) will be 10√3 m.

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➝ Trigonometry :- It is the branch of mathematics which deals with the measurement of angles and the problems allied with angles.