Question

The angle of elevation of the top of a tower,
from a point on the ground and at a distance
of 160 m from its foot, is found to be 60°.
Find the height of the tower.​

Answer 1

I hope it will help you . Thank you

Answer 2

Given :-

Distance = 160m

Angle of deviation = 60°

To Find :-

The height of the tower.

Solution :-

Let the given values be in the shape of a right angled triangle with A, B and C as it's vertices and angle B being 90°.

From the question we have,

$tan\: 60°\: =\: {\dfrac{AB}{BC}}$

On inserting the values in the formula

We get ,

$tan\: 60°\: =\: {\dfrac{AB}{160}}$

we know that, tan 60° = √3

therefore

${\sqrt{3}}\: =\: {\dfrac{AB}{160}}$

=> AB = √3 × 160 = 160√3

Therefore, distance is 160√3 m