Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower

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Answer 1

Answer:

Given the tower is 30m away from point A.

Given angle of elevation of top of tower is 30.

Let the height of tower be x

tan 30=

$\frac{bc}{ab}$

$\frac{1}{ \sqrt{3} } = \frac{x}{30}$

$x = \frac{30}{ \sqrt{3} } . \frac{ \sqrt{3} }{ \sqrt{3} } = \frac{30 \times \sqrt{3} }{3}$

$= 10 \sqrt{3}$

$height \: of \: tower \: = 10 \sqrt{3} = 10 \times 1.732$

$= 17.32m.$

$hope \: this \: helps \: you...$

Answer 2

Explanation:

Let us consider the height of the tower as AB, the distance between the foot of the tower to the point on the ground as BC.

In ΔABC, trigonometric ratio involving AB, BC and ∠C is tan θ.

tan C = AB/BC

tan 30° = AB/30

1/√3 = AB/30

AB = 30/√3

= (30 × √3) / (√3 × √3)

= (30√3)/3

= 10√3

Height of tower AB = 10√3 m.