Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower


​

Answer 1

Answer:

10√3 m

Explanation:

Let the triangle be ABC where AB is the height of the tower and BC is 30 m, while the angle away from the foot is 30°. (/_C = 30° and /_B = 90°)

We need to find the height of th tower i.e. AB.

In ∆ABC

tan C = AB/BC

tan 30° = AB/BC

1/√3 = AB/30

AB = 30/√3

Multiply and divide by √3

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3 m

Hence, the height of the tower is 10√3 m.

Answer 2

Answer:

I know you XD..

Yes I know you..

Khushi (◕ᴗ◕✿)

Good morning !!